What is 3(x^2+y)-(4+2x^2)=9 ?

The solution to 3(x^2+y)-(4+2x^2)=9 is Parabola with (h,k)=(0, 13/3),p=-3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3(x^2+y)-(4+2x^2)=9

3 (x^{2} + y) - (4 + 2 x^{2}) = 9

(h, k) = (0, \frac{13}{3}), p = - \frac{3}{4}

Solution steps

3 (x^{2} + y) - (4 + 2 x^{2}) = 9

Rewrite

3 (x^{2} + y) - (4 + 2 x^{2}) - 9 = 0

in the standard form

4 (- \frac{3}{4}) (y - \frac{13}{3}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{13}{3}), p = - \frac{3}{4}

y^{2} = - 20 (x - 2)

4 x^{2} = 32 (2 - y)

\frac{x}{2} - \frac{1}{2} = \frac{y - 1}{x + 3}

(y - 2)^{2} = 4 x

yy + x = 15

What is 3(x^2+y)-(4+2x^2)=9 ?
The solution to 3(x^2+y)-(4+2x^2)=9 is Parabola with (h,k)=(0, 13/3),p=-3/4