What is x/2-1/2 =(y-1)/(x+3) ?

The solution to x/2-1/2 =(y-1)/(x+3) is Parabola with (h,k)=(-1,-1),p= 1/2

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x/2-1/2 =(y-1)/(x+3)

\frac{x}{2} - \frac{1}{2} = \frac{y - 1}{x + 3}

(h, k) = (- 1, - 1), p = \frac{1}{2}

Solution steps

\frac{x}{2} - \frac{1}{2} = \frac{y - 1}{x + 3}

Rewrite

\frac{x}{2} - \frac{1}{2} - \frac{y - 1}{x + 3} = 0

in the standard form

4 \cdot \frac{1}{2} (y - (- 1)) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 1), p = \frac{1}{2}

(y - 2)^{2} = 4 x

yy + x = 15

(y + 9)^{2} = - 16 (x - 1)

5 x^{2} + 9 y = 45

(y + 2)^{2} = - 10 (x + 6)

What is x/2-1/2 =(y-1)/(x+3) ?
The solution to x/2-1/2 =(y-1)/(x+3) is Parabola with (h,k)=(-1,-1),p= 1/2