(x^2}{16}-\frac{y^2)/9 =1

解答

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

(h, k) = (0, 0), a = 4, b = 3

求解步骤

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

将

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

改写为标准双曲线方程形式

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

因此双曲线的性质为:

(h, k) = (0, 0), a = 4, b = 3

a sy m pt o t es 9 y^{2} - 4 x^{2} = 36

x^{2} - y^{2} \geq 1

d i rec t r i x x^{2} = - 28 y

v er t i ces f (x) = - x^{2} + 4 x - 3

3 y + 4 x = - 2 x^{2} - 14