What is the eccentricity (y^2)/(64)-(x^2)/(36)=1 ?

The eccentricity (y^2)/(64)-(x^2)/(36)=1 is 5/4

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eccentricity (y^2)/(64)-(x^2)/(36)=1

eccentricity

\frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1

\frac{5}{4}

Solution steps

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

\frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 8, b = 6

= \frac{8 ^{2} + 6 ^{2}}{8}

Refine

= \frac{5}{4}

\frac{x ^{2}}{9} - \frac{y ^{2}}{25} = 1

\frac{y ^{2}}{25} - \frac{x ^{2}}{16} = 1

\frac{( x + 1 ) ^{2}}{4} - (y - 5)^{2} = 4

9 x^{2} - 16 y^{2} = 144

\frac{x ^{2}}{100} - \frac{y ^{2}}{64} = 1

What is the eccentricity (y^2)/(64)-(x^2)/(36)=1 ?
The eccentricity (y^2)/(64)-(x^2)/(36)=1 is 5/4