What is the eccentricity (x^2)/9-(y^2)/(25)=1 ?

The eccentricity (x^2)/9-(y^2)/(25)=1 is (sqrt(34))/3

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eccentricity (x^2)/9-(y^2)/(25)=1

eccentricity

\frac{x ^{2}}{9} - \frac{y ^{2}}{25} = 1

\frac{34}{3}

Solution steps

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

\frac{x ^{2}}{9} - \frac{y ^{2}}{25} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 5

= \frac{3 ^{2} + 5 ^{2}}{3}

Refine

= \frac{34}{3}

\frac{y ^{2}}{25} - \frac{x ^{2}}{16} = 1

\frac{( x + 1 ) ^{2}}{4} - (y - 5)^{2} = 4

9 x^{2} - 16 y^{2} = 144

\frac{x ^{2}}{100} - \frac{y ^{2}}{64} = 1

9 y^{2} - 49 x^{2} = 441

What is the eccentricity (x^2)/9-(y^2)/(25)=1 ?
The eccentricity (x^2)/9-(y^2)/(25)=1 is (sqrt(34))/3