What is the center 7x^2-9y^2-14x+72y-200=0 ?

The center 7x^2-9y^2-14x+72y-200=0 is (1,4)

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center 7x^2-9y^2-14x+72y-200=0

center

7 x^{2} - 9 y^{2} - 14 x + 72 y - 200 = 0

(1, 4)

Solution steps

7 x^{2} - 9 y^{2} - 14 x + 72 y - 200 = 0

Rewrite

7 x^{2} - 9 y^{2} - 14 x + 72 y - 200 = 0

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{3 ^{2}} - \frac{( y - 4 ) ^{2}}{( 7 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 4), a = 3, b = 7

And the center is:

(1, 4)

x^{2} - (y - 4)^{2} = 1

4 x^{2} - 24 x - 25 y^{2} + 250 y - 489 = 0

\frac{( x - 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{16} = 1

\frac{( y - 5 ) ^{2}}{16} - \frac{( x - 4 ) ^{2}}{64} = 1

4 x^{2} - \frac{1}{2} y^{2} + 8 x + 2 y - 2 = 0

What is the center 7x^2-9y^2-14x+72y-200=0 ?
The center 7x^2-9y^2-14x+72y-200=0 is (1,4)