What is the center ((y-5)^2)/(16)-((x-4)^2)/(64)=1 ?

The center ((y-5)^2)/(16)-((x-4)^2)/(64)=1 is (4,5)

Popular >

center ((y-5)^2)/(16)-((x-4)^2)/(64)=1

center

\frac{( y - 5 ) ^{2}}{16} - \frac{( x - 4 ) ^{2}}{64} = 1

(4, 5)

Solution steps

\frac{( y - 5 ) ^{2}}{16} - \frac{( x - 4 ) ^{2}}{64} = 1

Rewrite

\frac{( y - 5 ) ^{2}}{16} - \frac{( x - 4 ) ^{2}}{64} = 1

in the form of a standard hyperbola equation

\frac{( y - 5 ) ^{2}}{4 ^{2}} - \frac{( x - 4 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (4, 5), a = 4, b = 8

And the center is:

(4, 5)

4 x^{2} - \frac{1}{2} y^{2} + 8 x + 2 y - 2 = 0

y^{2} - x^{2} = 1

9 x^{2} - 18 x - 24 y - 63 = 4 y^{2}

\frac{( x - 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{1} = 1

9 x^{2} - 36 x - 4 y^{2} - 24 y - 36 = 0

What is the center ((y-5)^2)/(16)-((x-4)^2)/(64)=1 ?
The center ((y-5)^2)/(16)-((x-4)^2)/(64)=1 is (4,5)