What is the center (x^2)/(36)-(y^2)/(16)=1 ?

The center (x^2)/(36)-(y^2)/(16)=1 is (0,0)

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center (x^2)/(36)-(y^2)/(16)=1

center

\frac{x ^{2}}{36} - \frac{y ^{2}}{16} = 1

(0, 0)

Solution steps

\frac{x ^{2}}{36} - \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{36} - \frac{y ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} - \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 6, b = 4

And the center is:

(0, 0)

\frac{( x + 5 ) ^{2}}{64} - \frac{( y - 1 ) ^{2}}{36} = 1

\frac{( x - 3 ) ^{2}}{25} - \frac{( y + 4 ) ^{2}}{36} = 1

7 x^{2} - 9 y^{2} - 14 x + 72 y - 200 = 0

x^{2} - (y - 4)^{2} = 1

4 x^{2} - 24 x - 25 y^{2} + 250 y - 489 = 0

What is the center (x^2)/(36)-(y^2)/(16)=1 ?
The center (x^2)/(36)-(y^2)/(16)=1 is (0,0)