What is the center 9x^2-y^2-72x+8y+119=0 ?

The center 9x^2-y^2-72x+8y+119=0 is (4,4)

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center 9x^2-y^2-72x+8y+119=0

center

9 x^{2} - y^{2} - 72 x + 8 y + 119 = 0

(4, 4)

Solution steps

9 x^{2} - y^{2} - 72 x + 8 y + 119 = 0

Rewrite

9 x^{2} - y^{2} - 72 x + 8 y + 119 = 0

in the form of a standard hyperbola equation

\frac{( x - 4 ) ^{2}}{1 ^{2}} - \frac{( y - 4 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (4, 4), a = 1, b = 3

And the center is:

(4, 4)

\frac{y ^{2}}{1} - \frac{x ^{2}}{4} = 1

x^{2} - y^{2} - 6 x = 16

\frac{( y - 4 ) ^{2}}{81} - \frac{( x + 5 ) ^{2}}{36} = 1

3 x^{2} - y^{2} - 12 x + 4 y + 2 = 0

\frac{x ^{2}}{49} - \frac{y ^{2}}{36} = 1

What is the center 9x^2-y^2-72x+8y+119=0 ?
The center 9x^2-y^2-72x+8y+119=0 is (4,4)