What is the center (y^2)/(16)-(x^2)/(25)=1 ?

The center (y^2)/(16)-(x^2)/(25)=1 is (0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

center (y^2)/(16)-(x^2)/(25)=1

center

\frac{y ^{2}}{16} - \frac{x ^{2}}{25} = 1

(0, 0)

Solution steps

\frac{y ^{2}}{16} - \frac{x ^{2}}{25} = 1

Rewrite

\frac{y ^{2}}{16} - \frac{x ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{4 ^{2}} - \frac{( x - 0 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 5

And the center is:

(0, 0)

y^{2} - 2 x^{2} = 1

- 9 x^{2} + 16 y^{2} - 90 x + 32 y - 353 = 0

25 x^{2} - 16 y^{2} + 50 x - 32 y - 391 = 0

x^{2} - 2 y^{2} + 3 x + 4 y = 2

\frac{( x - 5 ) ^{2}}{4} - \frac{( y - 3 ) ^{2}}{9} = 1

What is the center (y^2)/(16)-(x^2)/(25)=1 ?
The center (y^2)/(16)-(x^2)/(25)=1 is (0,0)