What is the center ((x-5)^2)/4-((y-3)^2)/9 =1 ?

The center ((x-5)^2)/4-((y-3)^2)/9 =1 is (5,3)

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center ((x-5)^2)/4-((y-3)^2)/9 =1

center

\frac{( x - 5 ) ^{2}}{4} - \frac{( y - 3 ) ^{2}}{9} = 1

(5, 3)

Solution steps

\frac{( x - 5 ) ^{2}}{4} - \frac{( y - 3 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{4} - \frac{( y - 3 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 5 ) ^{2}}{2 ^{2}} - \frac{( y - 3 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, 3), a = 2, b = 3

And the center is:

(5, 3)

4 y^{2} - 9 x^{2} + 8 y - 54 x - 113 = 0

y^{2} - x^{2} = \frac{9}{25}

9 x^{2} - 16 y^{2} - 108 x + 128 y + 212 = 0

y^{2} = x^{2} - 1

x^{2} - y^{2} - 4 x - 2 y - 1 = 0

What is the center ((x-5)^2)/4-((y-3)^2)/9 =1 ?
The center ((x-5)^2)/4-((y-3)^2)/9 =1 is (5,3)