What is the center x^2+36y-32x-y^2=75 ?

The center x^2+36y-32x-y^2=75 is (16,18)

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center x^2+36y-32x-y^2=75

center

x^{2} + 36 y - 32 x - y^{2} = 75

(16, 18)

Solution steps

x^{2} + 36 y - 32 x - y^{2} = 75

Rewrite

x^{2} + 36 y - 32 x - y^{2} = 75

in the form of a standard hyperbola equation

\frac{( x - 16 ) ^{2}}{( 7 ) ^{2}} - \frac{( y - 18 ) ^{2}}{( 7 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (16, 18), a = 7, b = 7

And the center is:

(16, 18)

- 3 x^{2} + 2 y^{2} + 6 x - 7 y = 7

(\frac{x - 3}{16})^{2} - \frac{( y - 1 ) ^{2}}{9} = 1

(x - y - 3) \cdot (x + y + 3) = 16

9 = 2 y - y^{2} - 6 \cdot (- x^{2})

4 x^{2} + 9 y^{2} + 3 x - 18 y^{2} + 37 = 0

What is the center x^2+36y-32x-y^2=75 ?
The center x^2+36y-32x-y^2=75 is (16,18)