What is the center (x-y-3)*(x+y+3)=16 ?

The center (x-y-3)*(x+y+3)=16 is (0,-3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

center (x-y-3)*(x+y+3)=16

center

(x - y - 3) \cdot (x + y + 3) = 16

(0, - 3)

Solution steps

(x - y - 3) (x + y + 3) = 16

Rewrite

(x - y - 3) (x + y + 3) = 16

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - ( - 3 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, - 3), a = 4, b = 4

And the center is:

(0, - 3)

9 = 2 y - y^{2} - 6 \cdot (- x^{2})

4 x^{2} + 9 y^{2} + 3 x - 18 y^{2} + 37 = 0

9 y^{2} - x^{2} - 36 y - 6 x + 18 = 0

\frac{( x - 2 ) ^{2}}{9} - \frac{( y + 2 ) ^{2}}{9} = 1

\frac{( y - ( - 2 ) ) ^{2}}{9} - \frac{( x - 5 ) ^{2}}{27} = 1