What is the center ((x-1)^2)/9-(y^2)/4 =1 ?

The center ((x-1)^2)/9-(y^2)/4 =1 is (1,0)

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center ((x-1)^2)/9-(y^2)/4 =1

center

\frac{( x - 1 ) ^{2}}{9} - \frac{y ^{2}}{4} = 1

(1, 0)

Solution steps

\frac{( x - 1 ) ^{2}}{9} - \frac{y ^{2}}{4} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{9} - \frac{y ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{3 ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 0), a = 3, b = 2

And the center is:

(1, 0)

\frac{( y - 2 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{25} = 1

\frac{y ^{2}}{25} - x^{2} = 1

- 4 x^{2} + y^{2} + 8 y - 20 = 0

\frac{x ^{2}}{4} - \frac{y ^{2}}{6} = - 1

4 x^{2} + 8 x - 4 y^{2} + 12 y - 3 = 0

What is the center ((x-1)^2)/9-(y^2)/4 =1 ?
The center ((x-1)^2)/9-(y^2)/4 =1 is (1,0)