What is the center ((y-2)^2)/9-((x+1)^2)/(25)=1 ?

The center ((y-2)^2)/9-((x+1)^2)/(25)=1 is (-1,2)

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center ((y-2)^2)/9-((x+1)^2)/(25)=1

center

\frac{( y - 2 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{25} = 1

(- 1, 2)

Solution steps

\frac{( y - 2 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{25} = 1

Rewrite

\frac{( y - 2 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( y - 2 ) ^{2}}{3 ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 2), a = 3, b = 5

And the center is:

(- 1, 2)

\frac{y ^{2}}{25} - x^{2} = 1

- 4 x^{2} + y^{2} + 8 y - 20 = 0

\frac{x ^{2}}{4} - \frac{y ^{2}}{6} = - 1

4 x^{2} + 8 x - 4 y^{2} + 12 y - 3 = 0

\frac{( x - 5 ) ^{2}}{1} - \frac{( y - 4 ) ^{2}}{1} = 1

What is the center ((y-2)^2)/9-((x+1)^2)/(25)=1 ?
The center ((y-2)^2)/9-((x+1)^2)/(25)=1 is (-1,2)