What is the center 16x^2-9y^2-144=0 ?

The center 16x^2-9y^2-144=0 is (0,0)

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center 16x^2-9y^2-144=0

center

16 x^{2} - 9 y^{2} - 144 = 0

(0, 0)

Solution steps

16 x^{2} - 9 y^{2} - 144 = 0

Rewrite

16 x^{2} - 9 y^{2} - 144 = 0

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} - \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3, b = 4

And the center is:

(0, 0)

x^{2} - 3 y^{2} - 2 x - 6 y + 7 = 0

9 (x - 1)^{2} - 16 (y + 2)^{2} = 144

\frac{( x - 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

\frac{y ^{2}}{4} - \frac{x ^{2}}{9} = 1

4 x^{2} - y^{2} - 24 x - 4 y + 28 = 0