What is the center 4x^2-y^2-24x-4y+28=0 ?

The center 4x^2-y^2-24x-4y+28=0 is (3,-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

center 4x^2-y^2-24x-4y+28=0

center

4 x^{2} - y^{2} - 24 x - 4 y + 28 = 0

(3, - 2)

Solution steps

4 x^{2} - y^{2} - 24 x - 4 y + 28 = 0

Rewrite

4 x^{2} - y^{2} - 24 x - 4 y + 28 = 0

in the form of a standard hyperbola equation

\frac{( x - 3 ) ^{2}}{1 ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, - 2), a = 1, b = 2

And the center is:

(3, - 2)

16 x^{2} - 9 y^{2} = 144

\frac{x ^{2}}{7} - \frac{7 y ^{2}}{42} = 1

4 y^{2} - 49 x^{2} - 392 x + 16 y - 964 = 0

\frac{y ^{2}}{9} - \frac{x ^{2}}{16} = 1

x^{2} - y^{2} = 16

What is the center 4x^2-y^2-24x-4y+28=0 ?
The center 4x^2-y^2-24x-4y+28=0 is (3,-2)