What is the center-9x^2+4y^2-36x-16y-164=0 ?

The center-9x^2+4y^2-36x-16y-164=0 is (-2,2)

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center-9x^2+4y^2-36x-16y-164=0

center

- 9 x^{2} + 4 y^{2} - 36 x - 16 y - 164 = 0

(- 2, 2)

Solution steps

- 9 x^{2} + 4 y^{2} - 36 x - 16 y - 164 = 0

Rewrite

- 9 x^{2} + 4 y^{2} - 36 x - 16 y - 164 = 0

in the form of a standard hyperbola equation

\frac{( y - 2 ) ^{2}}{6 ^{2}} - \frac{( x - ( - 2 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 2), a = 6, b = 4

And the center is:

(- 2, 2)

- x^{2} + y^{2} = 1

11 x^{2} - 25 y^{2} + 22 x + 250 y - 889 = 0

16 x^{2} - 9 y^{2} - 144 = 0

x^{2} - 3 y^{2} - 2 x - 6 y + 7 = 0

9 (x - 1)^{2} - 16 (y + 2)^{2} = 144

What is the center-9x^2+4y^2-36x-16y-164=0 ?
The center-9x^2+4y^2-36x-16y-164=0 is (-2,2)