What is the center+(x^2}{49}-\frac{y^2)/9 =1 ?

The center+(x^2}{49}-\frac{y^2)/9 =1 is (0,0)

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center+(x^2}{49}-\frac{y^2)/9 =1

center

+ \frac{x ^{2}}{49} - \frac{y ^{2}}{9} = 1

(0, 0)

Solution steps

\frac{x ^{2}}{49} - \frac{y ^{2}}{9} = 1

Rewrite

+ \frac{x ^{2}}{49} - \frac{y ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 7, b = 3

And the center is:

(0, 0)

5 x^{2} - 2 y^{2} + 10 x - 12 y = 23

\frac{x ^{2}}{4} - \frac{y ^{2}}{16} = 1

16 y^{2} - x^{2} + 2 x + 64 y + 47 = 0

25 x^{2} - 16 y^{2} + 50 x + 128 y - 631 = 0

- 9 x^{2} + 4 y^{2} - 36 x - 16 y - 164 = 0

What is the center+(x^2}{49}-\frac{y^2)/9 =1 ?
The center+(x^2}{49}-\frac{y^2)/9 =1 is (0,0)