What is 25(x+2)^2+y=(x-7)^2-81 ?

The solution to 25(x+2)^2+y=(x-7)^2-81 is Parabola with (h,k)=(-19/8 , 27/8),p=-1/96

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25(x+2)^2+y=(x-7)^2-81

25 (x + 2)^{2} + y = (x - 7)^{2} - 81

(h, k) = (- \frac{19}{8}, \frac{27}{8}), p = - \frac{1}{96}

Solution steps

25 (x + 2)^{2} + y = (x - 7)^{2} - 81

Rewrite

25 (x + 2)^{2} + y = (x - 7)^{2} - 81

in the standard form

4 (- \frac{1}{96}) (y - \frac{27}{8}) = (x - (- \frac{19}{8}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{19}{8}, \frac{27}{8}), p = - \frac{1}{96}

- 2 x^{2} + 6 x - 2 y - 1 = 0

x = - 4 y^{2}

x^{2} = 24 (y - 8)

f (x) = - 2 x^{2} + 2 f (x) in d (- 6)

4 x^{2} + 7 x + 12 k (x) - 3 = 0

What is 25(x+2)^2+y=(x-7)^2-81 ?
The solution to 25(x+2)^2+y=(x-7)^2-81 is Parabola with (h,k)=(-19/8 , 27/8),p=-1/96