What is 4x^2+7x+12k(x)-3=0 ?

The solution to 4x^2+7x+12k(x)-3=0 is Parabola with (h,k)=(-7/8 , 97/192),p=-3/4

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4x^2+7x+12k(x)-3=0

4 x^{2} + 7 x + 12 k (x) - 3 = 0

(h, k) = (- \frac{7}{8}, \frac{97}{192}), p = - \frac{3}{4}

Solution steps

4 x^{2} + 7 x + 12 y - 3 = 0

Rewrite

4 x^{2} + 7 x + 12 y - 3 = 0

in the standard form

4 (- \frac{3}{4}) (y - \frac{97}{192}) = (x - (- \frac{7}{8}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{7}{8}, \frac{97}{192}), p = - \frac{3}{4}

4 x - 2 x^{2} + y = 6

x^{2} = \frac{1}{2} y

x = y^{2} + 2 y + 4

x = y^{2} + 2 y + 2

y^{2} = x + 144

What is 4x^2+7x+12k(x)-3=0 ?
The solution to 4x^2+7x+12k(x)-3=0 is Parabola with (h,k)=(-7/8 , 97/192),p=-3/4