What is the foci ((x^2))/(36)-((y^2))/(25)=1 ?

The foci ((x^2))/(36)-((y^2))/(25)=1 is (sqrt(61),0),(-sqrt(61),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci ((x^2))/(36)-((y^2))/(25)=1

foci

\frac{( x ^{2} )}{36} - \frac{( y ^{2} )}{25} = 1

(61, 0), (- 61, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{36} - \frac{y ^{2}}{25} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 6, b = 5

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 6^{2} + 5^{2} : 61

(0 + 61, 0), (0 - 61, 0)

Refine

(61, 0), (- 61, 0)

y^{2} - x^{2} = \frac{1}{25}

y^{2} - 4 x^{2} < 1

x^{2} - 16 y^{2} = 64

(\frac{( x ^{2} )}{27}) - \frac{( ( y ) ^{2} )}{36} = 1

x^{2} - y^{2} - 6 x + 16 y - 119 = 0

What is the foci ((x^2))/(36)-((y^2))/(25)=1 ?
The foci ((x^2))/(36)-((y^2))/(25)=1 is (sqrt(61),0),(-sqrt(61),0)