What is the foci (((x^2))/(27))-(((y)^2))/(36)=1 ?

The foci (((x^2))/(27))-(((y)^2))/(36)=1 is (3sqrt(7),0),(-3sqrt(7),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (((x^2))/(27))-(((y)^2))/(36)=1

foci

(\frac{( x ^{2} )}{27}) - \frac{( ( y ) ^{2} )}{36} = 1

(37, 0), (- 37, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{27} - \frac{y ^{2}}{36} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 33, b = 6

(0 + c, 0), (0 - c, 0)

Compute

c :

c = (33)^{2} + 6^{2} : 37

(0 + 37, 0), (0 - 37, 0)

Refine

(37, 0), (- 37, 0)

x^{2} - y^{2} - 6 x + 16 y - 119 = 0

9 x^{2} - 25 y^{2} = 900

(\frac{x - 5}{8})^{2} - (\frac{y + 2}{7})^{2} = 1

3 x^{2} - y^{2} = 3

(\frac{x ^{2}}{16}) - (\frac{y ^{2}}{9}) = 1

What is the foci (((x^2))/(27))-(((y)^2))/(36)=1 ?
The foci (((x^2))/(27))-(((y)^2))/(36)=1 is (3sqrt(7),0),(-3sqrt(7),0)