What is the foci ((y-0)^2)/(1^2)-((3x-0)^2)/(90)=1 ?

The foci ((y-0)^2)/(1^2)-((3x-0)^2)/(90)=1 is (0,sqrt(11)),(0,-sqrt(11))

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foci ((y-0)^2)/(1^2)-((3x-0)^2)/(90)=1

foci

\frac{( y - 0 ) ^{2}}{1 ^{2}} - \frac{( 3 x - 0 ) ^{2}}{90} = 1

(0, 11), (0, - 11)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{( y - 0 ) ^{2}}{1 ^{2}} - \frac{( 3 x - 0 ) ^{2}}{90} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 1, b = 10

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1^{2} + 10^{2} : 11

(0, 0 + 11), (0, 0 - 11)

Refine

(0, 11), (0, - 11)

- \frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1

\frac{( x - 5 ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{16} = 1

\frac{( x - 0 ) ^{2}}{16} - \frac{( y - 0 ) ^{2}}{9} = 1

\frac{( x - 4 ) ^{2}}{49} - \frac{( y + 6 ) ^{2}}{9} = 1

\frac{( x ^{2} )}{36} - \frac{( y ^{2} )}{25} = 1

What is the foci ((y-0)^2)/(1^2)-((3x-0)^2)/(90)=1 ?
The foci ((y-0)^2)/(1^2)-((3x-0)^2)/(90)=1 is (0,sqrt(11)),(0,-sqrt(11))