What is the foci ((x-3)^2)/(8^2)-((y-2)^2)/(8^2)=1 ?

The foci ((x-3)^2)/(8^2)-((y-2)^2)/(8^2)=1 is (3+8sqrt(2),2),(3-8sqrt(2),2)

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foci ((x-3)^2)/(8^2)-((y-2)^2)/(8^2)=1

foci

\frac{( x - 3 ) ^{2}}{8 ^{2}} - \frac{( y - 2 ) ^{2}}{8 ^{2}} = 1

(3 + 82, 2), (3 - 82, 2)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{( x - 3 ) ^{2}}{8 ^{2}} - \frac{( y - 2 ) ^{2}}{8 ^{2}} = 1 :

Right-left Hyperbola with

(h, k) = (3, 2), a = 8, b = 8

(3 + c, 2), (3 - c, 2)

Compute

c :

c = 8^{2} + 8^{2} : 82

(3 + 82, 2), (3 - 82, 2)

\frac{x ^{2}}{49} - \frac{y ^{2}}{81} = 1

\frac{y ^{2}}{6} - \frac{x ^{2}}{11} = 1

4 x^{2} - y^{2} - 32 x + 60 = 0

\frac{x ^{2}}{625} - \frac{y ^{2}}{3600} = 1

5 x^{2} - 4 y^{2} - 40 x + 24 y + 24 = 0

What is the foci ((x-3)^2)/(8^2)-((y-2)^2)/(8^2)=1 ?
The foci ((x-3)^2)/(8^2)-((y-2)^2)/(8^2)=1 is (3+8sqrt(2),2),(3-8sqrt(2),2)