What is the foci (y^2)/6-(x^2)/(11)=1 ?

The foci (y^2)/6-(x^2)/(11)=1 is (0,sqrt(17)),(0,-sqrt(17))

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foci (y^2)/6-(x^2)/(11)=1

foci

\frac{y ^{2}}{6} - \frac{x ^{2}}{11} = 1

(0, 17), (0, - 17)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{6} - \frac{x ^{2}}{11} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 6, b = 11

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 6^{2} + 11^{2} : 17

(0, 0 + 17), (0, 0 - 17)

Refine

(0, 17), (0, - 17)

4 x^{2} - y^{2} - 32 x + 60 = 0

\frac{x ^{2}}{625} - \frac{y ^{2}}{3600} = 1

5 x^{2} - 4 y^{2} - 40 x + 24 y + 24 = 0

\frac{y ^{2}}{25} - \frac{x ^{2}}{64} = 1

9 y^{2} + 36 y - 4 x^{2} - 32 x - 64 = 0

What is the foci (y^2)/6-(x^2)/(11)=1 ?
The foci (y^2)/6-(x^2)/(11)=1 is (0,sqrt(17)),(0,-sqrt(17))