What is the foci 4x^2-y^2-6y-25=0 ?

The foci 4x^2-y^2-6y-25=0 is (2sqrt(5),-3),(-2sqrt(5),-3)

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foci 4x^2-y^2-6y-25=0

foci

4 x^{2} - y^{2} - 6 y - 25 = 0

(25, - 3), (- 25, - 3)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

4 x^{2} - y^{2} - 6 y - 25 = 0 :

Right-left Hyperbola with

(h, k) = (0, - 3), a = 2, b = 4

(0 + c, - 3), (0 - c, - 3)

Compute

c :

c = 2^{2} + 4^{2} : 25

(0 + 25, - 3), (0 - 25, - 3)

Refine

(25, - 3), (- 25, - 3)

\frac{( y - 3 ) ^{2}}{16} - \frac{( x + 4 ) ^{2}}{25} = 1

16 x^{2} - y^{2} - 64 x - 2 y + 47 = 0

\frac{( x - 1 ) ^{2}}{16} - \frac{( y - 7 ) ^{2}}{20} = 1

y^{2} - 9 x^{2} - 8 y - 54 x - 81 = 0

\frac{( x - 3 ) ^{2}}{8 ^{2}} - \frac{( y - 2 ) ^{2}}{8 ^{2}} = 1

What is the foci 4x^2-y^2-6y-25=0 ?
The foci 4x^2-y^2-6y-25=0 is (2sqrt(5),-3),(-2sqrt(5),-3)