What is the foci 4x^2-9y^2+3x+18y+91=0 ?

The foci 4x^2-9y^2+3x+18y+91=0 is (-3/8 ,(24+sqrt(20683))/(24)),(-3/8 ,(24-sqrt(20683))/(24))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 4x^2-9y^2+3x+18y+91=0

foci

4 x^{2} - 9 y^{2} + 3 x + 18 y + 91 = 0

(- \frac{3}{8}, \frac{24 + 20683}{24}), (- \frac{3}{8}, \frac{24 - 20683}{24})

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

4 x^{2} - 9 y^{2} + 3 x + 18 y + 91 = 0 :

Up-down Hyperbola with

(h, k) = (- \frac{3}{8}, 1), a = \frac{1591}{12}, b = \frac{1591}{8}

(- \frac{3}{8}, 1 + c), (- \frac{3}{8}, 1 - c)

Compute

c :

c = (\frac{1591}{12})^{2} + (\frac{1591}{8})^{2} : \frac{20683}{24}

(- \frac{3}{8}, 1 + \frac{20683}{24}), (- \frac{3}{8}, 1 - \frac{20683}{24})

Refine

(- \frac{3}{8}, \frac{24 + 20683}{24}), (- \frac{3}{8}, \frac{24 - 20683}{24})

4 x^{2} - 25 y^{2} = 100

\frac{y ^{2}}{3} - \frac{x ^{2}}{3} = 1

y^{2} - x^{2} = \frac{4}{25}

\frac{( y + 3 ) ^{2}}{10} - \frac{( x - 3 ) ^{2}}{20} = 1

\frac{x ^{2}}{64} - \frac{y ^{2}}{- 39} = 1

What is the foci 4x^2-9y^2+3x+18y+91=0 ?
The foci 4x^2-9y^2+3x+18y+91=0 is (-3/8 ,(24+sqrt(20683))/(24)),(-3/8 ,(24-sqrt(20683))/(24))