What is the foci y^2-x^2= 4/25 ?

The foci y^2-x^2= 4/25 is (0,(2sqrt(2))/5),(0,-(2sqrt(2))/5)

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foci y^2-x^2= 4/25

foci

y^{2} - x^{2} = \frac{4}{25}

(0, \frac{2 2}{5}), (0, - \frac{2 2}{5})

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

y^{2} - x^{2} = \frac{4}{25} :

Up-down Hyperbola with

(h, k) = (0, 0), a = \frac{2}{5}, b = \frac{2}{5}

(0, 0 + c), (0, 0 - c)

Compute

c :

c = (\frac{2}{5})^{2} + (\frac{2}{5})^{2} : \frac{2 2}{5}

(0, 0 + \frac{2 2}{5}), (0, 0 - \frac{2 2}{5})

Refine

(0, \frac{2 2}{5}), (0, - \frac{2 2}{5})

\frac{( y + 3 ) ^{2}}{10} - \frac{( x - 3 ) ^{2}}{20} = 1

\frac{x ^{2}}{64} - \frac{y ^{2}}{- 39} = 1

- \frac{x ^{2}}{144} + \frac{y ^{2}}{25} = 1

1 - \frac{x ^{2}}{4} + (y - 1)^{2} = 0

x^{2} - y^{2} = 4 x

What is the foci y^2-x^2= 4/25 ?
The foci y^2-x^2= 4/25 is (0,(2sqrt(2))/5),(0,-(2sqrt(2))/5)