What is the foci ((x-h)^2}{64}-\frac{(y-k)^2)/9 =1 ?

The foci ((x-h)^2}{64}-\frac{(y-k)^2)/9 =1 is (h+sqrt(73),k),(h-sqrt(73),k)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci ((x-h)^2}{64}-\frac{(y-k)^2)/9 =1

foci

\frac{( x - h ) ^{2}}{64} - \frac{( y - k ) ^{2}}{9} = 1

(h + 73, k), (h - 73, k)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{( x - h ) ^{2}}{64} - \frac{( y - k ) ^{2}}{9} = 1 :

Right-left Hyperbola with

(h, k) = (h, k), a = 8, b = 3

(h + c, k), (h - c, k)

Compute

c :

c = 8^{2} + 3^{2} : 73

(h + 73, k), (h - 73, k)

\frac{( y + 2 ) ^{2}}{16} - \frac{( x + 3 ) ^{2}}{9} = 1

\frac{( y - 2 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{16} = 1

12 y^{2} - 4 x^{2} + 16 x + 72 y + 44 = 0

\frac{y ^{2}}{45} - \frac{x ^{2}}{36} = 1

y^{2} - 4 x^{2} + 16 x - 2 y = 31

What is the foci ((x-h)^2}{64}-\frac{(y-k)^2)/9 =1 ?
The foci ((x-h)^2}{64}-\frac{(y-k)^2)/9 =1 is (h+sqrt(73),k),(h-sqrt(73),k)