What is the foci 2x^2-7y^2-16x+14y=-11 ?

The foci 2x^2-7y^2-16x+14y=-11 is (7,1),(1,1)

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foci 2x^2-7y^2-16x+14y=-11

foci

2 x^{2} - 7 y^{2} - 16 x + 14 y = - 11

(7, 1), (1, 1)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

2 x^{2} - 7 y^{2} - 16 x + 14 y = - 11 :

Right-left Hyperbola with

(h, k) = (4, 1), a = 7, b = 2

(4 + c, 1), (4 - c, 1)

Compute

c :

c = 7^{2} + 2^{2} : 3

(4 + 3, 1), (4 - 3, 1)

Refine

(7, 1), (1, 1)

9 x^{2} - 4 y^{2} - 36 x + 8 y - 4 = 0

\frac{( x - h ) ^{2}}{64} - \frac{( y - k ) ^{2}}{9} = 1

\frac{( y + 2 ) ^{2}}{16} - \frac{( x + 3 ) ^{2}}{9} = 1

\frac{( y - 2 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{16} = 1

12 y^{2} - 4 x^{2} + 16 x + 72 y + 44 = 0

What is the foci 2x^2-7y^2-16x+14y=-11 ?
The foci 2x^2-7y^2-16x+14y=-11 is (7,1),(1,1)