What is the foci 9x^2-4y^2-18x-16y-43=0 ?

The foci 9x^2-4y^2-18x-16y-43=0 is (1+sqrt(13),-2),(1-sqrt(13),-2)

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foci 9x^2-4y^2-18x-16y-43=0

foci

9 x^{2} - 4 y^{2} - 18 x - 16 y - 43 = 0

(1 + 13, - 2), (1 - 13, - 2)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

9 x^{2} - 4 y^{2} - 18 x - 16 y - 43 = 0 :

Right-left Hyperbola with

(h, k) = (1, - 2), a = 2, b = 3

(1 + c, - 2), (1 - c, - 2)

Compute

c :

c = 2^{2} + 3^{2} : 13

(1 + 13, - 2), (1 - 13, - 2)

9 x^{2} - 25 y^{2} = 225

\frac{x ^{2}}{9} - \frac{y ^{2}}{64} = 1

x = x^{2} - \frac{y ^{2}}{9}

11 x^{2} - 7 y^{2} = 77

9 x^{2} - 4 y^{2} = 144

What is the foci 9x^2-4y^2-18x-16y-43=0 ?
The foci 9x^2-4y^2-18x-16y-43=0 is (1+sqrt(13),-2),(1-sqrt(13),-2)