What is the foci (x^2)/9-(y^2)/(64)=1 ?

The foci (x^2)/9-(y^2)/(64)=1 is (sqrt(73),0),(-sqrt(73),0)

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foci (x^2)/9-(y^2)/(64)=1

foci

\frac{x ^{2}}{9} - \frac{y ^{2}}{64} = 1

(73, 0), (- 73, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{9} - \frac{y ^{2}}{64} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 8

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 3^{2} + 8^{2} : 73

(0 + 73, 0), (0 - 73, 0)

Refine

(73, 0), (- 73, 0)

x = x^{2} - \frac{y ^{2}}{9}

11 x^{2} - 7 y^{2} = 77

9 x^{2} - 4 y^{2} = 144

\frac{( x - 5 ) ^{2}}{16} - \frac{( y - 4 ) ^{2}}{64} = 1

8 x^{2} - 2 y^{2} = 16

What is the foci (x^2)/9-(y^2)/(64)=1 ?
The foci (x^2)/9-(y^2)/(64)=1 is (sqrt(73),0),(-sqrt(73),0)