焦点 5x^2-2y^2+10x-12y=23

解答

焦点

5 x^{2} - 2 y^{2} + 10 x - 12 y = 23

(- 1 + 7, - 3), (- 1 - 7, - 3)

求解步骤

(h + c, k), (h - c, k)

计算双曲线性质

5 x^{2} - 2 y^{2} + 10 x - 12 y = 23 :

左右开口双曲线，

(h, k) = (- 1, - 3), a = 2, b = 5

(- 1 + c, - 3), (- 1 - c, - 3)

计算

c :

c = 2^{2} + 5^{2} : 7

(- 1 + 7, - 3), (- 1 - 7, - 3)

f oc i 4 x^{2} - 9 y^{2} - 24 x - 36 y - 36 = 0

f oc i 9 x^{2} = 4 y^{2} - 12

f oc i \frac{( x ^{2} )}{4} - 0.2 y^{2} = 1

f oc i \frac{( x + 1 ) ^{2}}{9} - \frac{( y - 4 ) ^{2}}{49} = 1

f oc i \frac{( x + 2 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{5} = 1