What is the foci ((x+1)^2)/9-((y-4)^2)/(49)=1 ?

The foci ((x+1)^2)/9-((y-4)^2)/(49)=1 is (-1+sqrt(58),4),(-1-sqrt(58),4)

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foci ((x+1)^2)/9-((y-4)^2)/(49)=1

foci

(- 1 + 58, 4), (- 1 - 58, 4)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{( x + 1 ) ^{2}}{9} - \frac{( y - 4 ) ^{2}}{49} = 1 :

Right-left Hyperbola with

(h, k) = (- 1, 4), a = 3, b = 7

(- 1 + c, 4), (- 1 - c, 4)

Compute

c :

c = 3^{2} + 7^{2} : 58

(- 1 + 58, 4), (- 1 - 58, 4)

What is the foci ((x+1)^2)/9-((y-4)^2)/(49)=1 ?
The foci ((x+1)^2)/9-((y-4)^2)/(49)=1 is (-1+sqrt(58),4),(-1-sqrt(58),4)