What is the foci 9x^2-2y^2=18 ?

The foci 9x^2-2y^2=18 is (sqrt(11),0),(-sqrt(11),0)

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foci 9x^2-2y^2=18

foci

9 x^{2} - 2 y^{2} = 18

(11, 0), (- 11, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

9 x^{2} - 2 y^{2} = 18 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} + 3^{2} : 11

(0 + 11, 0), (0 - 11, 0)

Refine

(11, 0), (- 11, 0)

\frac{x ^{2}}{49} - \frac{y ^{2}}{36} = 1

36 y^{2} - 4 x^{2} = 144

x^{2} - 4 y^{2} + 8 x + 16 y - 4 = 0

5 x^{2} - 2 y^{2} + 10 x - 12 y = 23

4 x^{2} - 9 y^{2} - 24 x - 36 y - 36 = 0

What is the foci 9x^2-2y^2=18 ?
The foci 9x^2-2y^2=18 is (sqrt(11),0),(-sqrt(11),0)