What is the foci y^2-4x^2=36 ?

The foci y^2-4x^2=36 is (0,3sqrt(5)),(0,-3sqrt(5))

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foci y^2-4x^2=36

foci

y^{2} - 4 x^{2} = 36

(0, 35), (0, - 35)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

y^{2} - 4 x^{2} = 36 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 6, b = 3

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 6^{2} + 3^{2} : 35

(0, 0 + 35), (0, 0 - 35)

Refine

(0, 35), (0, - 35)

\frac{( y - 2 ) ^{2}}{14} - \frac{( x + 6 ) ^{2}}{3} = 4

3 x^{2} - 13 y^{2} - 30 x + 52 y = 16

4 x^{2} + 9 y^{2} + 3 x - 18 y^{2} + 37 = 0

9 x^{2} - 2 y^{2} = 18

\frac{x ^{2}}{49} - \frac{y ^{2}}{36} = 1

What is the foci y^2-4x^2=36 ?
The foci y^2-4x^2=36 is (0,3sqrt(5)),(0,-3sqrt(5))