What is the foci (x^2)/(25)-(y^2)/(81)=1 ?

The foci (x^2)/(25)-(y^2)/(81)=1 is (sqrt(106),0),(-sqrt(106),0)

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foci (x^2)/(25)-(y^2)/(81)=1

foci

\frac{x ^{2}}{25} - \frac{y ^{2}}{81} = 1

(106, 0), (- 106, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{25} - \frac{y ^{2}}{81} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 5, b = 9

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 5^{2} + 9^{2} : 106

(0 + 106, 0), (0 - 106, 0)

Refine

(106, 0), (- 106, 0)

3 x^{2} - 4 y^{2} = 12

5 x^{2} - 5 y^{2} + 20 x - 60 y = 185

\frac{x ^{2}}{25} - \frac{y ^{2}}{36} = 1

25 y^{2} - 16 x^{2} = 400

\frac{x ^{2}}{9} - \frac{y ^{2}}{49} = 1

What is the foci (x^2)/(25)-(y^2)/(81)=1 ?
The foci (x^2)/(25)-(y^2)/(81)=1 is (sqrt(106),0),(-sqrt(106),0)