What is the foci (x^2)/(25)-(y^2)/(36)=1 ?

The foci (x^2)/(25)-(y^2)/(36)=1 is (sqrt(61),0),(-sqrt(61),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2)/(25)-(y^2)/(36)=1

foci

\frac{x ^{2}}{25} - \frac{y ^{2}}{36} = 1

(61, 0), (- 61, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{25} - \frac{y ^{2}}{36} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 5, b = 6

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 5^{2} + 6^{2} : 61

(0 + 61, 0), (0 - 61, 0)

Refine

(61, 0), (- 61, 0)

25 y^{2} - 16 x^{2} = 400

\frac{x ^{2}}{9} - \frac{y ^{2}}{49} = 1

4 x^{2} - 3 y^{2} - 8 x - 8 = 0

\frac{( x - 3 ) ^{2}}{25} - \frac{( y + 1 ) ^{2}}{25} = 1

\frac{x ^{2}}{5625} - \frac{y ^{2}}{1600} = 1

What is the foci (x^2)/(25)-(y^2)/(36)=1 ?
The foci (x^2)/(25)-(y^2)/(36)=1 is (sqrt(61),0),(-sqrt(61),0)