What is the foci (x^2)/(4^2)-(y^2)/(3^2)=1 ?

The foci (x^2)/(4^2)-(y^2)/(3^2)=1 is (5,0),(-5,0)

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foci (x^2)/(4^2)-(y^2)/(3^2)=1

foci

\frac{x ^{2}}{4 ^{2}} - \frac{y ^{2}}{3 ^{2}} = 1

(5, 0), (- 5, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{4 ^{2}} - \frac{y ^{2}}{3 ^{2}} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 4, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 4^{2} + 3^{2} : 5

(0 + 5, 0), (0 - 5, 0)

Refine

(5, 0), (- 5, 0)

- 9 x^{2} + 4 y^{2} = 36

- 4 x^{2} + y^{2} = 16

- \frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1

\frac{y ^{2}}{25} - \frac{( x - 2 ) ^{2}}{0} = 1

\frac{y ^{2}}{1} - \frac{x ^{2}}{4} = 1

What is the foci (x^2)/(4^2)-(y^2)/(3^2)=1 ?
The foci (x^2)/(4^2)-(y^2)/(3^2)=1 is (5,0),(-5,0)