What is the foci-4x^2+y^2=16 ?

The foci-4x^2+y^2=16 is (0,2sqrt(5)),(0,-2sqrt(5))

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foci-4x^2+y^2=16

foci

- 4 x^{2} + y^{2} = 16

(0, 25), (0, - 25)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

- 4 x^{2} + y^{2} = 16 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 4, b = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 4^{2} + 2^{2} : 25

(0, 0 + 25), (0, 0 - 25)

Refine

(0, 25), (0, - 25)

- \frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1

\frac{y ^{2}}{25} - \frac{( x - 2 ) ^{2}}{0} = 1

\frac{y ^{2}}{1} - \frac{x ^{2}}{4} = 1

\frac{x ^{2}}{25} - \frac{y ^{2}}{144} = 1

\frac{( y - 3 ) ^{2}}{36} - \frac{( x + 2 ) ^{2}}{4} = 1

What is the foci-4x^2+y^2=16 ?
The foci-4x^2+y^2=16 is (0,2sqrt(5)),(0,-2sqrt(5))