What is the vertices 4x^2-25y^2-40x-150y-225=0 ?

The vertices 4x^2-25y^2-40x-150y-225=0 is (10,-3),(0,-3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices 4x^2-25y^2-40x-150y-225=0

vertices

4 x^{2} - 25 y^{2} - 40 x - 150 y - 225 = 0

(10, - 3), (0, - 3)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

4 x^{2} - 25 y^{2} - 40 x - 150 y - 225 = 0 :

Right-left Hyperbola with

(h, k) = (5, - 3), a = 5, b = 2

(5 + 5, - 3), (5 - 5, - 3)

Refine

(10, - 3), (0, - 3)

\frac{y ^{2}}{9} - \frac{x ^{2}}{1} = 1

4 x^{2} - \frac{1}{2} y^{2} + 8 x - 2 y = 2

4 (x - 2)^{2} - 9 (y + 4)^{2} = 1

- 4 x^{2} + y^{2} - 2 y = 3

\frac{y ^{2}}{225} - \frac{x ^{2}}{64} = 1

What is the vertices 4x^2-25y^2-40x-150y-225=0 ?
The vertices 4x^2-25y^2-40x-150y-225=0 is (10,-3),(0,-3)