What is the vertices (y^2)/9-(x^2)/1 =1 ?

The vertices (y^2)/9-(x^2)/1 =1 is (0,3),(0,-3)

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vertices (y^2)/9-(x^2)/1 =1

vertices

\frac{y ^{2}}{9} - \frac{x ^{2}}{1} = 1

(0, 3), (0, - 3)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{y ^{2}}{9} - \frac{x ^{2}}{1} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 3, b = 1

(0, 0 + 3), (0, 0 - 3)

Refine

(0, 3), (0, - 3)

4 x^{2} - \frac{1}{2} y^{2} + 8 x - 2 y = 2

4 (x - 2)^{2} - 9 (y + 4)^{2} = 1

- 4 x^{2} + y^{2} - 2 y = 3

\frac{y ^{2}}{225} - \frac{x ^{2}}{64} = 1

\frac{y ^{2}}{1} - \frac{x ^{2}}{36} = 1

What is the vertices (y^2)/9-(x^2)/1 =1 ?
The vertices (y^2)/9-(x^2)/1 =1 is (0,3),(0,-3)