What is the vertices 9/125 y^2-1/5 x^2=1 ?

The vertices 9/125 y^2-1/5 x^2=1 is (0,(5sqrt(5))/3),(0,-(5sqrt(5))/3)

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vertices 9/125 y^2-1/5 x^2=1

vertices

\frac{9}{125} y^{2} - \frac{1}{5} x^{2} = 1

(0, \frac{5 5}{3}), (0, - \frac{5 5}{3})

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{9}{125} y^{2} - \frac{1}{5} x^{2} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = \frac{5 5}{3}, b = 5

(0, 0 + \frac{5 5}{3}), (0, 0 - \frac{5 5}{3})

Refine

(0, \frac{5 5}{3}), (0, - \frac{5 5}{3})

y^{2} - \frac{x ^{2}}{4} = 1

\frac{( y - 3 ) ^{2}}{16} - \frac{( x + 4 ) ^{2}}{25} = 1

x^{2} - y^{2} + 2 y = 2

9 y^{2} + 36 y - 4 x^{2} - 32 x - 64 = 0

- 25 x^{2} + 9 y^{2} = 225

What is the vertices 9/125 y^2-1/5 x^2=1 ?
The vertices 9/125 y^2-1/5 x^2=1 is (0,(5sqrt(5))/3),(0,-(5sqrt(5))/3)