What is the vertices x^2-y^2+2y=2 ?

The vertices x^2-y^2+2y=2 is (1,1),(-1,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices x^2-y^2+2y=2

vertices

x^{2} - y^{2} + 2 y = 2

(1, 1), (- 1, 1)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

x^{2} - y^{2} + 2 y = 2 :

Right-left Hyperbola with

(h, k) = (0, 1), a = 1, b = 1

(0 + 1, 1), (0 - 1, 1)

Refine

(1, 1), (- 1, 1)

9 y^{2} + 36 y - 4 x^{2} - 32 x - 64 = 0

- 25 x^{2} + 9 y^{2} = 225

\frac{( y - 2 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{25} = 1

9 y^{2} - x^{2} + 54 y + 2 x + 62 = 0

x^{2} - y^{2} = 6