What is the vertices 4(y-3)^2-9(x-2)^2=36 ?

The vertices 4(y-3)^2-9(x-2)^2=36 is (2,6),(2,0)

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vertices 4(y-3)^2-9(x-2)^2=36

vertices

4 (y - 3)^{2} - 9 (x - 2)^{2} = 36

(2, 6), (2, 0)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

4 (y - 3)^{2} - 9 (x - 2)^{2} = 36 :

Up-down Hyperbola with

(h, k) = (2, 3), a = 3, b = 2

(2, 3 + 3), (2, 3 - 3)

Refine

(2, 6), (2, 0)

\frac{x ^{2}}{36} - \frac{( y - 10 ) ^{2}}{64} = 1

4 x^{2} - y^{2} + 32 x + 10 y + 38 = 0

4 x^{2} - y^{2} + 12 x + 5 = 0

\frac{y ^{2}}{36} - \frac{x ^{2}}{4} = 1

\frac{( x ^{2} )}{36} - \frac{( y ^{2} )}{25} = 1

What is the vertices 4(y-3)^2-9(x-2)^2=36 ?
The vertices 4(y-3)^2-9(x-2)^2=36 is (2,6),(2,0)