What is the vertices (y^2}{36}-\frac{x^2)/4 =1 ?

The vertices (y^2}{36}-\frac{x^2)/4 =1 is (0,6),(0,-6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices (y^2}{36}-\frac{x^2)/4 =1

vertices

\frac{y ^{2}}{36} - \frac{x ^{2}}{4} = 1

(0, 6), (0, - 6)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{y ^{2}}{36} - \frac{x ^{2}}{4} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 6, b = 2

(0, 0 + 6), (0, 0 - 6)

Refine

(0, 6), (0, - 6)

\frac{( x ^{2} )}{36} - \frac{( y ^{2} )}{25} = 1

16 x^{2} - y^{2} - 64 x - 2 y + 47 = 0

\frac{y ^{2}}{4 ^{2}} - \frac{x ^{2}}{3 ^{2}} = 1

\frac{( y + 2 ) ^{2}}{4} - \frac{( x - 1 ) ^{2}}{45} = 1

\frac{x ^{2}}{729} - \frac{y ^{2}}{484} = 1

What is the vertices (y^2}{36}-\frac{x^2)/4 =1 ?
The vertices (y^2}{36}-\frac{x^2)/4 =1 is (0,6),(0,-6)