What is the vertices 5y^2-x^2=25 ?

The vertices 5y^2-x^2=25 is (0,sqrt(5)),(0,-sqrt(5))

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vertices 5y^2-x^2=25

vertices

5 y^{2} - x^{2} = 25

(0, 5), (0, - 5)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

5 y^{2} - x^{2} = 25 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 5

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

\frac{( x - 3 ) ^{2}}{9} - \frac{y ^{2}}{4} = 1

\frac{y ^{2}}{49} - \frac{x ^{2}}{64} = 1

4 x^{2} - 3 y^{2} - 8 x - 8 = 0

\frac{x ^{2}}{2} - \frac{y ^{2}}{3} = 1

- 4 x^{2} + y^{2} + 16 x + 12 y + 16 = 0

What is the vertices 5y^2-x^2=25 ?
The vertices 5y^2-x^2=25 is (0,sqrt(5)),(0,-sqrt(5))