What is the vertices (y^2)/(49)-(x^2)/(64)=1 ?

The vertices (y^2)/(49)-(x^2)/(64)=1 is (0,7),(0,-7)

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vertices (y^2)/(49)-(x^2)/(64)=1

vertices

\frac{y ^{2}}{49} - \frac{x ^{2}}{64} = 1

(0, 7), (0, - 7)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{y ^{2}}{49} - \frac{x ^{2}}{64} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 7, b = 8

(0, 0 + 7), (0, 0 - 7)

Refine

(0, 7), (0, - 7)

4 x^{2} - 3 y^{2} - 8 x - 8 = 0

\frac{x ^{2}}{2} - \frac{y ^{2}}{3} = 1

- 4 x^{2} + y^{2} + 16 x + 12 y + 16 = 0

\frac{y ^{2}}{81} - \frac{x ^{2}}{64} = 1

\frac{( x ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{9} = 1

What is the vertices (y^2)/(49)-(x^2)/(64)=1 ?
The vertices (y^2)/(49)-(x^2)/(64)=1 is (0,7),(0,-7)