What is the vertices (x^2)/(27)-(y^2)/(72)=1 ?

The vertices (x^2)/(27)-(y^2)/(72)=1 is (3sqrt(3),0),(-3sqrt(3),0)

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vertices (x^2)/(27)-(y^2)/(72)=1

vertices

\frac{x ^{2}}{27} - \frac{y ^{2}}{72} = 1

(33, 0), (- 33, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{x ^{2}}{27} - \frac{y ^{2}}{72} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 33, b = 62

(0 + 33, 0), (0 - 33, 0)

Refine

(33, 0), (- 33, 0)

\frac{y ^{2}}{3} - \frac{x ^{2}}{1} = 1

4 x^{2} - 5 y^{2} + 30 y = 65

f (x) f (x) = x^{2} + 5 x + 6

\frac{( x + 4 ) ^{2}}{9} - \frac{( y - 8 ) ^{2}}{49} = 1

25 x^{2} - 9 y^{2} - 225 = 0

What is the vertices (x^2)/(27)-(y^2)/(72)=1 ?
The vertices (x^2)/(27)-(y^2)/(72)=1 is (3sqrt(3),0),(-3sqrt(3),0)